2(3x)=[.5(x+3+12)2]

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Solution for 2(3x)=[.5(x+3+12)2] equation:


Simplifying
2(3x) = [0.5(x + 3 + 12) * 2]

Remove parenthesis around (3x)
2 * 3x = [0.5(x + 3 + 12) * 2]

Multiply 2 * 3
6x = [0.5(x + 3 + 12) * 2]

Reorder the terms:
6x = [0.5(3 + 12 + x) * 2]

Combine like terms: 3 + 12 = 15
6x = [0.5(15 + x) * 2]

Reorder the terms for easier multiplication:
6x = [0.5 * 2(15 + x)]

Multiply 0.5 * 2
6x = [1(15 + x)]
6x = [(15 * 1 + x * 1)]
6x = [(15 + 1x)]
6x = [15 + 1x]

Remove brackets around [15 + 1x]
6x = 15 + 1x

Solving
6x = 15 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
6x + -1x = 15 + 1x + -1x

Combine like terms: 6x + -1x = 5x
5x = 15 + 1x + -1x

Combine like terms: 1x + -1x = 0
5x = 15 + 0
5x = 15

Divide each side by '5'.
x = 3

Simplifying
x = 3

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